а)10/2-с/2=(10-с)/2
б)(15у²-15у²+1)/3=1/3
в)(3а+3б-а+3)/3=(2а+3б+3)/3
г)(2б²-1-б²+5б)/б=(б²-1+5б)/б
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а)10/2-с/2=(10-с)/2
б)(15у²-15у²+1)/3=1/3
в)(3а+3б-а+3)/3=(2а+3б+3)/3
г)(2б²-1-б²+5б)/б=(б²-1+5б)/б