Ответ: 4 . ( 1/2)sin2x + √3/4 ; 5. 2cos2α .
Объяснение:
4 . sin( 30°+ x)cos(30° - x) = ( 1/2 )[ sin( 30°+ x - 30° +x ) + sin( 30°+ x+30°- x) ] =
=( 1/2)( sin2x + sin60°) = ( 1/2)sin2x + ( 1/2)* (√3/2) = ( 1/2)sin2x + √3/4 ;
5 . ( cos5α + cosα )/( cos2αcosα - sin2αsinα )=
= (2cos3αcos2α )/ ( cos3α ) = 2cos2α .
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Ответ: 4 . ( 1/2)sin2x + √3/4 ; 5. 2cos2α .
Объяснение:
4 . sin( 30°+ x)cos(30° - x) = ( 1/2 )[ sin( 30°+ x - 30° +x ) + sin( 30°+ x+30°- x) ] =
=( 1/2)( sin2x + sin60°) = ( 1/2)sin2x + ( 1/2)* (√3/2) = ( 1/2)sin2x + √3/4 ;
5 . ( cos5α + cosα )/( cos2αcosα - sin2αsinα )=
= (2cos3αcos2α )/ ( cos3α ) = 2cos2α .