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miaajoe
@miaajoe
August 2022
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Помогите пожалуйста, срочно
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sharadi
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₀∫¹ (2x +1)dx = ( 2x²/2 + x)| в пределах от 0 до 1= 1 +1 = 2
₀∫² (х³ -1)dx = ( х⁴/4 - x)|в пределах от 0 до 2 = 4 -2= 2
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Verified answer
₀∫¹ (2x +1)dx = ( 2x²/2 + x)| в пределах от 0 до 1= 1 +1 = 2₀∫² (х³ -1)dx = ( х⁴/4 - x)|в пределах от 0 до 2 = 4 -2= 2