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dasha77713
@dasha77713
June 2022
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anna2501v
А) (t-3)(t+5)=t²+5t-3t-15=t²+2t-15
б) (4х-7)(3х-8)=12х²-32х-21х+56=12х²-53х+56
в) (b-2)(b²+3b-4)=b³+3b²-4b-2b²-6b+8=b³+b²-10b+8
г) (n+7)(-n-4)=-n²-4n-7n-28=-n²-11n-28
д) (13р-1)(13р+1)=169р²-1
е) (a+b)(a²-ab+b²)=a³+b³
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Answers & Comments
б) (4х-7)(3х-8)=12х²-32х-21х+56=12х²-53х+56
в) (b-2)(b²+3b-4)=b³+3b²-4b-2b²-6b+8=b³+b²-10b+8
г) (n+7)(-n-4)=-n²-4n-7n-28=-n²-11n-28
д) (13р-1)(13р+1)=169р²-1
е) (a+b)(a²-ab+b²)=a³+b³