помогите пожалуйста, срочно. Created by TKotova1106. algebra-ru

помогите пожалуйста, срочно...

TKotova1106 @TKotova1106

July 2022 1 7 Report

помогите пожалуйста, срочно

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sangers1959

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Y=4-x² y=0 x=1 x=2
S=₁²/(4-x²-0)=₁²(4-x²)=(4x-x³/3) |²₁=4*2-2³/3-(4*1-1³/3)=8-8/3-(4-1/3)=
=8-8/3-4+1/3=4-7/3=4-2¹/₃=1²/₃.
Ответ: S=1²/₃=1,67 кв.ед. (б)

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Answers & Comments

Verified answer

6)^x+16>36 help me please...

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log 2 x 2 gt 1 budu blagodarna

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2*2^x-3*2^x-2=0 Help me...

oblast opredeleniya funkcii uln16 x

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22^x-32^x-2=0 Help me...