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cavid93267
@cavid93267
October 2021
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nKrynka
Решение
Применяем правило Лопиталя
limx-->0 (3x*ctg2x) = limx-->0 (3x*cos2x)/sin2x =
= limx-->0 (3x*cos2x)` / limx--> 0 (sin2x)` =
= limx-->0 [3*cos2x + 3x*(-2sin2x)] / limx-->0 (2cos2x) =
= (3 + 0) / (2*1) = 3/2 = 1,5
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Answers & Comments
Применяем правило Лопиталя
limx-->0 (3x*ctg2x) = limx-->0 (3x*cos2x)/sin2x =
= limx-->0 (3x*cos2x)` / limx--> 0 (sin2x)` =
= limx-->0 [3*cos2x + 3x*(-2sin2x)] / limx-->0 (2cos2x) =
= (3 + 0) / (2*1) = 3/2 = 1,5