Ответ:
Объяснение:
5)
(sin2a-2sina)/(cosa-1) = (2sina*cosa-2sina)/cosa-1) = =2sina(cosa-1)/(cosa-1)=2sina
6)
(cosa-sin2a)/(1-sin2a) = (cosa-2sina*cosa)/(1-2sina)= =cosa(1-2sina)/(1-2sina)=cosa
7)
(sinx-cosx)^2/(1-sin2x)=(sin²x-2sinx*cosx+cos²x)/(1-sin2x)= =(sin²x+cos^2x-2sinx*cosx)/(1-sin2x)==1-sin2x)/(1-sin2x)= 1
8)
(cos2a*tg2a)/2sina=(cos2a* sin2a/cos2a)/2sina=sin2a/2sina= =2sina*cosa/2sina=cosa
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Объяснение:
5)
(sin2a-2sina)/(cosa-1) = (2sina*cosa-2sina)/cosa-1) = =2sina(cosa-1)/(cosa-1)=2sina
6)
(cosa-sin2a)/(1-sin2a) = (cosa-2sina*cosa)/(1-2sina)= =cosa(1-2sina)/(1-2sina)=cosa
7)
(sinx-cosx)^2/(1-sin2x)=(sin²x-2sinx*cosx+cos²x)/(1-sin2x)= =(sin²x+cos^2x-2sinx*cosx)/(1-sin2x)==1-sin2x)/(1-sin2x)= 1
8)
(cos2a*tg2a)/2sina=(cos2a* sin2a/cos2a)/2sina=sin2a/2sina= =2sina*cosa/2sina=cosa