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WaRDotA
@WaRDotA
September 2021
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Помогите пожалуйста УПРОСТИТЕ ЛОГАРИФМЫ 50 баллов даю
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Verified answer
X^(logx 5) = 5
x^(2*logx 5) = x^(logx 25) = 25
x^(-logx 5) = x^(logx (1/5)) = 1/5
x^(-2*logx 5) = x^(logx (1/5^2)) = 1/5^2 = 1/25
|1/2|^(-3log 3) - не понятно, по какому основанию логарифм
2^(-3log (1/2)) - тоже не понятно, какое основание
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Answers & Comments
Verified answer
X^(logx 5) = 5x^(2*logx 5) = x^(logx 25) = 25
x^(-logx 5) = x^(logx (1/5)) = 1/5
x^(-2*logx 5) = x^(logx (1/5^2)) = 1/5^2 = 1/25
|1/2|^(-3log 3) - не понятно, по какому основанию логарифм
2^(-3log (1/2)) - тоже не понятно, какое основание