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olya9607
@olya9607
July 2022
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Помогите Пожалуйста вот:
1) (6а+1)(2а-3)=0
2) 7у-(3у-(8у-(5-6у)))
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lyubacha2
1) 12а^2-18a+2a-3=0
a(12a-18+2)=0
a=0 a=0 a=0 a=0
12a-18+2=0 12a=16 a=16/12 a= 1 1/3
2) 7y-(3y-(8y-(5-6y)))=0
7y-(3y-(8y-5+6y))=0
7y-(3y-8y+5-6y)=0
7y-3y+8y-5+6y=0
18y=5
y=5/18
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Answers & Comments
a(12a-18+2)=0
a=0 a=0 a=0 a=0
12a-18+2=0 12a=16 a=16/12 a= 1 1/3
2) 7y-(3y-(8y-(5-6y)))=0
7y-(3y-(8y-5+6y))=0
7y-(3y-8y+5-6y)=0
7y-3y+8y-5+6y=0
18y=5
y=5/18