Ответ:
дано
m(FeO) = 50 kg = 50000 g
w(пр ) = 15 %
---------------------
m(C)-?
m чист (FeO) = 50000 - (50000*15% / 100%) = 42500 g
FeO+C-->Fe+CO
M(FeO) = 72 g/mol
n(FeO) = m/M = 42500 / 72 = 590.3 mol
n(FeO) = n(C)
M(C) = 12 g/mol
m(C) = n*M = 590.3 * 12 = 7083.3 g = 7.08 kg
ответ 7.08 кг
Объяснение:
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Ответ:
дано
m(FeO) = 50 kg = 50000 g
w(пр ) = 15 %
---------------------
m(C)-?
m чист (FeO) = 50000 - (50000*15% / 100%) = 42500 g
FeO+C-->Fe+CO
M(FeO) = 72 g/mol
n(FeO) = m/M = 42500 / 72 = 590.3 mol
n(FeO) = n(C)
M(C) = 12 g/mol
m(C) = n*M = 590.3 * 12 = 7083.3 g = 7.08 kg
ответ 7.08 кг
Объяснение: