Ответ:
Объяснение:
3) АС²=АВ²+ВС²-2АВ*ВС cos 30°
АС²=1²+1²-2*1*1* √3/2=2-√3=
AC==
4) ∠ACD=∠D=90°/2=45° ∠ACB=180°-45°=135°
АB²=ВC²+AС²-2ВC*AС cos 135°
АB²=1²+1²-2*1*1* cos 135°= 2-2*(-√2/2)=2+√2
AB=
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Answers & Comments
Ответ:
Объяснение:
3) АС²=АВ²+ВС²-2АВ*ВС cos 30°
АС²=1²+1²-2*1*1* √3/2=2-√3=
AC=
=
4) ∠ACD=∠D=90°/2=45° ∠ACB=180°-45°=135°
АB²=ВC²+AС²-2ВC*AС cos 135°
АB²=1²+1²-2*1*1* cos 135°= 2-2*(-√2/2)=2+√2
AB=