Home
О нас
Products
Services
Регистрация
Войти
Поиск
way51
@way51
July 2022
1
8
Report
Помогите пожалуйста, заранее спасибо)))
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
au456
Verified answer
Sin a = 2√2cos a
sin^2 a+ cos ^2 a = 1
sin^2 a (1+(1/2√2)^2)=1
sin^2 a=8/9
sin a = 2√2/3
cos a =√2 sin a
cos^2 a (1+(1/√2)^2)=1
cos^2 a = 4/5
cos a = -2/√5. минус потому что в 3 четверти.
2 votes
Thanks 1
×
Report "Помогите пожалуйста, заранее спасибо)))..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Sin a = 2√2cos asin^2 a+ cos ^2 a = 1
sin^2 a (1+(1/2√2)^2)=1
sin^2 a=8/9
sin a = 2√2/3
cos a =√2 sin a
cos^2 a (1+(1/√2)^2)=1
cos^2 a = 4/5
cos a = -2/√5. минус потому что в 3 четверти.