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simbat00
@simbat00
July 2022
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vzhvzh
1)1/х-2а+1/х+2а +8а2 /4а2х-х3 =
2/х
1/х-2а+1/х+2а +8а2 /х(4а2-х2)
1) 1/х-2а+1/х+2а = х+2а+х-2а/х2-4а2 = 2х/х2-4а2
2) 2х/х2-4а2 +8а2/х(2а-х)(2а+х) = 2х/(х2-4а2) - 8а2/х(х-2а)(х+2а) = 2х2+8а2/х(х2-4а2) = 2(х2-4а2)/х(х2-4а2) = 2/х
на фотографии решение второго номера
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Answers & Comments
1/х-2а+1/х+2а +8а2 /х(4а2-х2)
1) 1/х-2а+1/х+2а = х+2а+х-2а/х2-4а2 = 2х/х2-4а2
2) 2х/х2-4а2 +8а2/х(2а-х)(2а+х) = 2х/(х2-4а2) - 8а2/х(х-2а)(х+2а) = 2х2+8а2/х(х2-4а2) = 2(х2-4а2)/х(х2-4а2) = 2/х
на фотографии решение второго номера