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ttimchuk26
@ttimchuk26
July 2022
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Помогите пожалуйста завтра экзамен!!!!!!!!!!!
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snow99
1.11. По теореме синусов:
AB/sinC = 2R,
2R = 3sqrt(2) : sqrt(2)/2 = 3sqrt(2) * 2/sqrt(2) = 6
R = 3 (см).
Ответ: Б)
1.12. AB = (3 - 3; - 4 - (-1)) = (0; -3)
|AB| = sqrt(0^2 + (-3)^2) = sqrt(9) = 3.
Ответ: В)
2.1.
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Answers & Comments
AB/sinC = 2R,
2R = 3sqrt(2) : sqrt(2)/2 = 3sqrt(2) * 2/sqrt(2) = 6
R = 3 (см).
Ответ: Б)
1.12. AB = (3 - 3; - 4 - (-1)) = (0; -3)
|AB| = sqrt(0^2 + (-3)^2) = sqrt(9) = 3.
Ответ: В)
2.1.