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vlada1805
@vlada1805
August 2021
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litanalove
1. a) 5y(3y -2) -(y -4)(y +4) = 15y² -10y -(y² -16) =15y² -10y -y² +16 =14y² -10y +16
b) (n +5)(n -8) +(n +7)² =n² -3n -40 +n² +14n +49 =2n² +11n +9
в) 8(a +k)² -16ak =8(a² +2ak +k²) -16ak =8a² +16ak +8k² -16ak =8a² +8k²
2. a) 25y^3 -y =y(25y² -1) = y(5y -1)(5y +1)
b) 7a² -28a +28 =7(a² -4a +4) =7(a -2)² =7(a -2)(a -2)
3. (2z +3)² -(2z +1)(4z +3) -2z, при z = -2
4z² +12z +9 -(8z² +10z +3) -2z =4z² +10z +9 -8z² -10z -3 =6 -4z² =6 -4*(-2)² =6 -4*2² =6 -4*4 =6 -16 = -10
4. b) m -2n -m² +4mn -4n² =(m -2n) -(m² -4mn +2n²) = (m -2n) -(m -2n)² =(m -2n)(1 -m +2n)
5. (x-1)² -2(x-1)(x+5) +(x+5)² =36
соберем выражение по формуле a²-2ab+b²=(a-b)²
(x-1 -(x+5))² =36
(x-1 -x -5)² =36
(-6)² =36
36 =36
что и требовалось доказать
1 votes
Thanks 1
ShpendOS
1a. 15y^2-10y-y^2+16=14y^2-10y+16 1б. n^2+5n-8n-40+n^2+14n+49=2n^2+11n+9 1в. 8a^2+16ak+8k^2-16ak=8a^2+8k^2 2a. 25y^3-y=y(25y^2-1)=y(5y-1)(5y+1) 2б. 7a^2-28a+28=7(a^2-4a+4)=7(a-2)^2 4a. 25m^2-n^2+2n-1=25m^2-(n^2-2n+1)=25m^2-(n-1)^2=(5m-n+1)(5m+n-1) 4б. m-2n-m^2+4mn-4n^2=m-2n-(m^2-4mn+4n^2)=m-2n-(m-2n)^2=(m-2n)(1-m+2n) 3. (2z+3)^2-(2z+1)(4z+3)-2z=4z^2+12z+9-8z^2-4z-6z-3-2z=-4z^2+6 при z=-2 -16+6=-10 5. (x-1)^2-2(x-1)(x+5)+(x+5)^2=36 ((x-1)-(x+5))^2=36 (x-1-x-5)^2=36 (-6)^2=36 36=36
1 votes
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Answers & Comments
b) (n +5)(n -8) +(n +7)² =n² -3n -40 +n² +14n +49 =2n² +11n +9
в) 8(a +k)² -16ak =8(a² +2ak +k²) -16ak =8a² +16ak +8k² -16ak =8a² +8k²
2. a) 25y^3 -y =y(25y² -1) = y(5y -1)(5y +1)
b) 7a² -28a +28 =7(a² -4a +4) =7(a -2)² =7(a -2)(a -2)
3. (2z +3)² -(2z +1)(4z +3) -2z, при z = -2
4z² +12z +9 -(8z² +10z +3) -2z =4z² +10z +9 -8z² -10z -3 =6 -4z² =6 -4*(-2)² =6 -4*2² =6 -4*4 =6 -16 = -10
4. b) m -2n -m² +4mn -4n² =(m -2n) -(m² -4mn +2n²) = (m -2n) -(m -2n)² =(m -2n)(1 -m +2n)
5. (x-1)² -2(x-1)(x+5) +(x+5)² =36
соберем выражение по формуле a²-2ab+b²=(a-b)²
(x-1 -(x+5))² =36
(x-1 -x -5)² =36
(-6)² =36
36 =36
что и требовалось доказать