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natanatakir
@natanatakir
October 2021
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tausinv
Verified answer
Log(sqrt(2))(x + y) = 2
3^x *7^y = 21
x + y > 0 - ОДЗ
2 * log(2)(x + y) = 2 - вынесли степень 1/2 из-под основания логарифма
log2(x + y) = 1
x + y = 2
3^x *7^y = 21
21 = 3^1 * 7^1
x + y = 2
3^x *7^y = 3^1 * 7^1
x = 1, y = 1 - подходит под ОДЗ
Ответ: (1,1)
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Answers & Comments
Verified answer
Log(sqrt(2))(x + y) = 23^x *7^y = 21
x + y > 0 - ОДЗ
2 * log(2)(x + y) = 2 - вынесли степень 1/2 из-под основания логарифма
log2(x + y) = 1
x + y = 2
3^x *7^y = 21
21 = 3^1 * 7^1
x + y = 2
3^x *7^y = 3^1 * 7^1
x = 1, y = 1 - подходит под ОДЗ
Ответ: (1,1)