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kendyzeyyn
@kendyzeyyn
August 2022
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fidanquliyeva19
А) f(x)=3x-4x^3, x=5
f(5)=3x-4x^3=3*5-4*5^3=15-500=-485
ə) f(x)=x^7-3x^6+3x^3-23, x=-1
f(-1)=-1-3-3-23=-30
б) f(x)=(1+2x)(2x-1), x=0,5=1/2
f(1/2)=(1+2*1/2)(2*1/2-1)=(1+1)*(1-1)=2*0=0
в) f(x)=x^2(x-5), x=-4
f(-4)=16(-4-5)=16*(-9)=-144
г) f(x)=
(x^2-1), x
=4
f(4)=
*15=2*15=30
2 votes
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Answers & Comments
f(5)=3x-4x^3=3*5-4*5^3=15-500=-485
ə) f(x)=x^7-3x^6+3x^3-23, x=-1
f(-1)=-1-3-3-23=-30
б) f(x)=(1+2x)(2x-1), x=0,5=1/2
f(1/2)=(1+2*1/2)(2*1/2-1)=(1+1)*(1-1)=2*0=0
в) f(x)=x^2(x-5), x=-4
f(-4)=16(-4-5)=16*(-9)=-144
г) f(x)=
f(4)=