Відповідь:
Покрокове пояснення:
1) x∈∅
2) sin(-2x-3π/4)=-√2/2
sin (-2x-3π/4)=-√2/2
sin(π-(-2x-3π/4))=-√2/2
-2x-3π/4=arcsin(-√2/2)
sin (7π/4+2x)=-√2/2
-2x-3π/4=-π/4
7π/4+2x=arcsin(-√2/2)
-2x-3π/4=-π/4+2kπ, k∈Z
7π/4+2x=-π/4
x=-π/4-kπ, k∈Z
7π/4+2x=-π/4+2kπ, k ∈Z
x=3π/4+kπ, k∈Z
x=0+kπ, k∈Z
x= cистема 3π/4+kπ
kπ
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Answers & Comments
Відповідь:
Покрокове пояснення:
1) x∈∅
2) sin(-2x-3π/4)=-√2/2
sin (-2x-3π/4)=-√2/2
sin(π-(-2x-3π/4))=-√2/2
-2x-3π/4=arcsin(-√2/2)
sin (7π/4+2x)=-√2/2
-2x-3π/4=-π/4
7π/4+2x=arcsin(-√2/2)
-2x-3π/4=-π/4+2kπ, k∈Z
7π/4+2x=-π/4
x=-π/4-kπ, k∈Z
7π/4+2x=-π/4+2kπ, k ∈Z
x=3π/4+kπ, k∈Z
x=0+kπ, k∈Z
x= cистема 3π/4+kπ
kπ