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Karinka9000
@Karinka9000
September 2021
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Гоша68
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A^3+b^3=(a+b)((a+b)^2-3ab)=5*(5^2-3*6)=5*7=35
a^3-b^3=(a-b)((a-b)^2+3ab)=2*(4+3*24)=152
2x-4-3y-9=-12 2x-3y=1
x+y=8 2x+2y=16 5y=15 y=3 x=5
3x+3-4y+12=-12 3x-4y=-27
x+y=12 3x+3y=36 7y=63 y=9 x=3
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Answers & Comments
Verified answer
A^3+b^3=(a+b)((a+b)^2-3ab)=5*(5^2-3*6)=5*7=35a^3-b^3=(a-b)((a-b)^2+3ab)=2*(4+3*24)=152
2x-4-3y-9=-12 2x-3y=1
x+y=8 2x+2y=16 5y=15 y=3 x=5
3x+3-4y+12=-12 3x-4y=-27
x+y=12 3x+3y=36 7y=63 y=9 x=3