Помогите пожалуйста.... Created by madina2503. algebra-ru

Помогите пожалуйста...

madina2503 @madina2503

July 2022 1 3 Report

Помогите пожалуйста...

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nafanya2014

Verified answer

=(х-1)·(3a-2b+c)
=(p-a)·(x-y-z)
=(a²+b²)·(p+q-r)
=(m²+1)·(a-b-c)
=a·(m+n)+b·(m+n)=(m+n)·(a+b)
=a·(x-y)+b·(x-y)=(x-y)·(a+b)
=a·(x-c)-b·(x-c)=(x-c)·(a-b)
=x²·(x+3)+3·(x+3)=(x+3)·(x²+3)
=m·(m+n)-5·(m+n)=(m+n)·(m-5)
=5y·(2a-b)+x·(2a-b)=(2a-b)·(5y+x)
=5a·(a-x)-7·(a-x)=(a-x)·(5a-7)
=(10a²-15ay)-(14ax-21xy)=5a·(2a-3y)-7x·(2a-3y)=(2a-3y)·(5a-7)
=(30ax-15a)-(34bx-17b)=15a·(2x-1)-17b·(2x-1)=(2x-1)·(15a-17b)
=(x-x³)+(x²-x⁴)=x·(1-x²)+x²·(1-x²)=(1-x²)·(x+x²)=(1-x²)·x·(1+x)

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madina2503 Огромное спасибо!!!))

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