sin377°=sin(360°+17°)=sin17°
cos407°=cos(360°+47°)=cos47°
sin377°-√3cos17°=sin17°-√3cos17°=2*((1/2)*sin17°-(√3/2)cos17°)=
=2*(sin30°sin17°-cos30°cos17°)=-2*(cos30°cos17°-sin30°sin17°)=-2cos(30°+17°)=-2cos47°
-2cos47°/cos47°=-2
Ответ -2.
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Verified answer
sin377°=sin(360°+17°)=sin17°
cos407°=cos(360°+47°)=cos47°
sin377°-√3cos17°=sin17°-√3cos17°=2*((1/2)*sin17°-(√3/2)cos17°)=
=2*(sin30°sin17°-cos30°cos17°)=-2*(cos30°cos17°-sin30°sin17°)=-2cos(30°+17°)=-2cos47°
-2cos47°/cos47°=-2
Ответ -2.