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hOmpeRG
@hOmpeRG
November 2021
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sedinalana
Verified answer
3
sina=-√(1-cosa)=-√(1-16/25)=-√(9/25)=-3/5
tga=sina/cosa=-3/5:(-4/5)+3/5*5/4=3/4
ctga=1/tga=1:3/4=4/3
4
tga=√3
cos²a=1:(1+tg²a)=1:(1+3)=1/4
cosa=-1/2
sina=-√(1-cosa)=-√(1-1/4)=-√(3/4)=-√3/2
ctga=1/tga=1/√3
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Answers & Comments
Verified answer
3sina=-√(1-cosa)=-√(1-16/25)=-√(9/25)=-3/5
tga=sina/cosa=-3/5:(-4/5)+3/5*5/4=3/4
ctga=1/tga=1:3/4=4/3
4
tga=√3
cos²a=1:(1+tg²a)=1:(1+3)=1/4
cosa=-1/2
sina=-√(1-cosa)=-√(1-1/4)=-√(3/4)=-√3/2
ctga=1/tga=1/√3