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diana03091994
@diana03091994
August 2021
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Помогите пожалуйста)))))))
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MizoriesKun
А)
√(17+2√30)=√(√15²+2√30+√2²) =√((√15+√2)²)=(√15+√2)²
б)
√(19-2√34)= √(√17²-2√34+√2²) = √((√17-√2)²)=(√17-√2)²
г)
⁴√(7+√48)= ⁴√(7+√(3*16)) = ⁴√(7+4√3)=⁴√(4+4√3 +3) =⁴√(2²+4√3 +√3²) =
= ⁴√(2+√3)²=√(2+√3)
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Answers & Comments
√(17+2√30)=√(√15²+2√30+√2²) =√((√15+√2)²)=(√15+√2)²
б)
√(19-2√34)= √(√17²-2√34+√2²) = √((√17-√2)²)=(√17-√2)²
г)
⁴√(7+√48)= ⁴√(7+√(3*16)) = ⁴√(7+4√3)=⁴√(4+4√3 +3) =⁴√(2²+4√3 +√3²) =
= ⁴√(2+√3)²=√(2+√3)