Помогите пожалуйста!. Created by bulavskaaana. algebra-ru

1) a) ( 0,3 *27 - 27 )² = ( 27 ( 0,3 - 1 )² = ( 27 * ( - 0,7 ))² = ( -18,9)²б) при а = -4 то 0,5 * 16 = 82) а) = = 3² = 9б) = = = 73) а) ( b^2+n)³ : b^6 = b^6+3n = b^6+3n : b^6 = b^3nb) y^2n-4 * y^4 * y^3n+4 = y^2n+4 * y^3n+4 = y^2n * y^3n+4 = y^5n+4

Помогите пожалуйста!...

bulavskaaana @bulavskaaana

August 2021 1 7 Report

Помогите пожалуйста!

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Trangkute1811 1) a) ( 0,3 *27 - 27 )² = ( 27 ( 0,3 - 1 )² = ( 27 * ( - 0,7 ))² = ( -18,9)²
б) при а = -4 то
0,5 * 16 = 8
2) а) $\frac{3^9 * 3^1^1}{3^1^8}$ = $\frac{3^2^0}{3^1^8} }$ = 3² = 9
б) $\frac{7^6 * 343}{49^4} } }$ = $\frac{7^6 * 7^3}{7^8} } } }$ = $\frac{7^9}{7^8} } } } }$ = 7
3) а) ( b^2+n)³ : b^6 = b^6+3n = b^6+3n : b^6 = b^3n
b) y^2n-4 * y^4 * y^3n+4 = y^2n+4 * y^3n+4 = y^2n * y^3n+4 = y^5n+4

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