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ttttt1997
@ttttt1997
July 2022
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mb17x
X²+y²-8x+2y+16=0
x²-8x+16+y²+2y+1-1=0
(x-4)²+(y+1)²-1=0
(x-4)²+(y+1)²=1
x₀=4
y₀=-1
r=1
A(1;4): 1+16-8+8+16=33
Ответ: (4;-1), r=1, точка А(1;4) не принадлежит данной окружности.
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Answers & Comments
x²-8x+16+y²+2y+1-1=0
(x-4)²+(y+1)²-1=0
(x-4)²+(y+1)²=1
x₀=4
y₀=-1
r=1
A(1;4): 1+16-8+8+16=33
Ответ: (4;-1), r=1, точка А(1;4) не принадлежит данной окружности.