Помогите пожалуйста!!!. Created by rustamkaloveR. algebra-ru

Помогите пожалуйста!!!...

rustamkaloveR @rustamkaloveR

March 2022 1 7 Report

Помогите пожалуйста!!!

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sangers1959

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1.
a) (343)^(1/3)*(125)^(1/5)*(25)^(1/5)=(7³)^(1/3)*(5³)^(1/5)*(5²)^(1/5)=
=7*(5⁵)^(1/5)=7*5=35.
б) 32^(1/5)*27^(1/3)-625^(1/4)=(2⁵)^(1/5)*(3³)^(1/3)-(5⁴)^(1/4)=2*3-4=6-4=2.
в) 8^(4/3)/8^(1/3)+9^(5/2)*9^(1/2)=16/2+243*3=8+729=737.
г) 5*25^(1/2)-(1/81)^(-1/4)+(4⁵/₆)⁰=5*5-3+1=25-3+1=23.
д)log₈32-log₈(1/2)=log₈2⁵-log₈2⁻¹=log₈2⁵+log₈2=log₂³(2⁵/2)=log₂2⁴/3=4/3=1¹/₃.
2,
a) 2*c²-2*c^(8/3)/c^(2/3)=2*(c²-c^(8/3-2/3))=2*(c₂-c^(6/3))=2*(c²-c²)=2*0=0.
б) ∛√(729*a¹²)=(3⁶*a¹²)^(1/6)=3*a².

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