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dianatlehuch090
@dianatlehuch090
August 2021
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m11m
X³-3x²-4x+12=0
(x³-3x²)-(4x-12)=0
x²(x-3)-4(x-3)=0
(x-3)(x²-4)=0
(x-3)(x-2)(x+2)=0
x-3=0 x-2=0 x+2=0
x=3 x=2 x=-2
Ответ: -2; 2; 3.
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dianatlehuch090
спасибо)
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Answers & Comments
(x³-3x²)-(4x-12)=0
x²(x-3)-4(x-3)=0
(x-3)(x²-4)=0
(x-3)(x-2)(x+2)=0
x-3=0 x-2=0 x+2=0
x=3 x=2 x=-2
Ответ: -2; 2; 3.