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Q1w2e3r4t4y8
@Q1w2e3r4t4y8
August 2022
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spiderg
1а)
1б)
2а)
2б)
3)
. При y=70:
2 votes
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Answers & Comments
1а)
1б)
2а)
2б)
3)
. При y=70: 