ПОМОГИТЕ, ПОЖАЛУЙСТА!!. Created by Pavel1241. algebra-ru

ПОМОГИТЕ, ПОЖАЛУЙСТА!!...

September 2021 1 11 Report

ПОМОГИТЕ, ПОЖАЛУЙСТА!!

Answers & Comments

Мпрмггнпшоиол ((a + 2b)²/3(a - 4b) - 3a/1) · (a² - 16b²)/(2a² - 10ab - b²) ÷ (4a + 16b)/(27a - 21) =
= (-9a) + 7 = 4
1) (a + 2b)²/3(a - 4b) - 3a/1 = (a + 2b)²/3(a - 4b) - (3(a - 4b) · 3a)/3(a - 4b) = ((a + 2b)²-
- (3(a - 4b) · 3a))/3(a - 4b) = (a² + 4ab + 4b² - (3a(3a - 12b)))/3(a - 4b) =
= (a² + 4ab + 4b² - (9a² - 36ab))/3(a - 4b) = (a²+4ab+4b²-9a²+36ab)/3(a - 4b) =
= (a²-9a²+4ab+36ab+4b²)/3(a - 4b) = ((-8a²)+40ab+4b²)/3(a - 4b)
2) ((-8a²) + 40ab + 4b²)/3(a - 4b) · (a² - 16b²)/(2a² - 10ab - b²) = (-4)(2a² - 10ab - b²)/
/3(a - 4b) · (a - 4b)(a + 4b)/(2a² - 10ab - b²) = (-4)(2a² - 10ab - b²)(a - 4b)(a + 4b)/
/3(a - 4b)(2a² - 10ab - b²) = (-4)(a + 4b)/3
3) (-4)(a + 4b)/3 ÷ (4a + 16b)/(27a - 21) = (-4)(a + 4b)/3 · (27a - 21)/(4a + 16b) =
= (-4)(a + 4b) · 3(9a - 7)/3 · 4(a + 4b) = (-1)(9a - 7) = (-9a) + 7
Найти значение выражения (-9a) + 7 при a = 1/3, b = (-7/3).
(-9a) + 7 = (-9) · 1/3 + 7 = (-9/3) + 7 = (-3) +7 = 4
·

1 votes Thanks 1

Answers & Comments

pomogite pozhalujsta 1pri vyrabotke uslovnogo pishevogo refleksa u sobaki pisha

iz chego delayut magnitnuyu strelku

pomogite pozhalujsta ochen srochno nado na bumage my vidim zelyonyj cvet vybe

pomogite pozhalujsta ochen srochno nado6bbbd634174370c1cdd368a3992fadf5 64264

pomogite pozhalujsta ochen srochno nado skolko naturalnyh chisel menshih 100

pomogite pozhalujsta ochen srochno kakie vetra preobladayut v lesostepi stepi

v tundre arkticheskie vetra pomogite pozhalujsta

pomogite pozhalujsta kakaya tipichnaya pogoda v subarkticheskom klimate

pomogite pozhalujsta nuzhno reshit eto uravnenie h2so4naohmolekulyarnoe urav

reshite pozhalujsta dannoe uravnenie nuzhno sostavit molekulyarnoe i ionnoe urav710424bad49672121ee31db1a9c545bc 75401

рекомендуемые вопросы

Helpful Links

Helpful Social