Ответ:

Объяснение:

1) (y+1)³ -y/4 ·(2y+3)²=7

y³+3y²+3y+1 -y/4 ·(4y²+12y+9)=7

y³+3y²+3y+1-y³-3y² -9/4 ·y=7

(12-9)/4 ·y=7-1

y=6·4/3=2·4=8

2) (8x-3)²x-(4x-1)³=7

(64x²-48x+9)x-(64x³-3·16x²+12x-1)=7

64x³-48x²+9x-64x³+48x²-12x+1=7

3x=1-7

x=-6/3=-2

3) (2x -1/3)³-x(2x -1/3)²=?

4) (4y-3)³-y(8y-9)²=0

64y³-9·16y²+12y·9-27-y(64y²-144y+81)=0

64y³-144y²+108y-27-64y³+144y²-81y=0

27y=27

y=27/27=1

5) x³+3x²+3x+1=0

(x+1)³=0

x+1=0

x=-1

6) 8y³-36y²+54y-27=0

(2y)³-3·(2y)²·3+3·2y·9-3³=0

(2y-3)³=0

2y-3=0

2y=3

y=3/2=1,5