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210393
@210393
August 2022
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ПОМОГИТЕ ПОЖАЛУЙСТА.
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sedinalana
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ОДЗ 2-x≥0⇒x≤2
√(2-x)=a
a+4/(a+3)=2
a²+3a+4-2a-6=0
a²+a-2=0
a1+a2=-1 U a1*a2=-2
a1=-2⇒√(2-x)=-2 нет решения
a2=1⇒√(2-x)=1⇒2-x=1⇒x=1
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Answers & Comments
Verified answer
ОДЗ 2-x≥0⇒x≤2√(2-x)=a
a+4/(a+3)=2
a²+3a+4-2a-6=0
a²+a-2=0
a1+a2=-1 U a1*a2=-2
a1=-2⇒√(2-x)=-2 нет решения
a2=1⇒√(2-x)=1⇒2-x=1⇒x=1