3а)(5√2+2√7)√2-√56=5√2*√2+2√7*√2-√56=5*2+2√14-√(4*14)=
=10+2√14-2√14=10
3б)(3√2+7)(7-3√2)=(7 + 3√2)(7-3√2)=7²-(3√2)²=49-18=31
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3а)(5√2+2√7)√2-√56=5√2*√2+2√7*√2-√56=5*2+2√14-√(4*14)=
=10+2√14-2√14=10
3б)(3√2+7)(7-3√2)=(7 + 3√2)(7-3√2)=7²-(3√2)²=49-18=31