Verified answer

у=3х+√х  х≥0

у=3х + х¹/²

у'=3*1*x¹⁻¹ + (1/2)*x¹/²⁻¹

y'=3+0,5*x^(-1/2)=0,5/√x + 3

y'(2)=0,5/√2  + 3=0,5/√2 + 3=3 + 1/(2√2)

или 3+√2/4.