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ПОМОГИТЕ , ПОЖАЛУЙСТА!...

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ПОМОГИТЕ , ПОЖАЛУЙСТА!

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zarembo73 Решение на фото.
ОДЗ:
log(2)x>0;
log(2)x>log(2)1;
x>1;

log(2)(2√2x)>0;
log(2)(2√2x)>log(2)1;
2√2x>1;
x>√2/4.
Корень х=1/2 не подходит, так как 1/2∉ ОДЗ.
Ответ: 8.

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