1) Mr (H20) = (1•2)+16=2+16=18
Вариант "В"
2) Mr (CO2) = 12+(16•2)=12+32=44
Вариант "Б"
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Answers & Comments
1) Mr (H20) = (1•2)+16=2+16=18
Вариант "В"
2) Mr (CO2) = 12+(16•2)=12+32=44
Вариант "Б"