Ответ: C ) tg²α .
Объяснение:
[ tg( π + α ) * sin( 3π/2 + α ) ] / [ cos( π - α ) * tg( 3π/2 - α ) ] =
= ( tgα * (- cosα ) )/ (- cosα * ctgα ) = - sinα /( - cos²α/sinα ) = sin²α/cos²α = tg²α .
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Ответ: C ) tg²α .
Объяснение:
[ tg( π + α ) * sin( 3π/2 + α ) ] / [ cos( π - α ) * tg( 3π/2 - α ) ] =
= ( tgα * (- cosα ) )/ (- cosα * ctgα ) = - sinα /( - cos²α/sinα ) = sin²α/cos²α = tg²α .