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@Masla
August 2022
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MusikaWinx
F(x)=3(√x)+4x
x0=1
Δx=3
найти
Δf(x)
Δf(x)=f(x0+Δx)-f(x0)=f(1+3)-f(1)=f(4
)-f(1)=
=(3
√4+4·4)-(3√1+4·1)=(6+16)-(3+4)=22-7=15
1 votes
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Masla
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TARTILLO
Verified answer
Простейшее задание на производные функции.
Δf(x) = f(x+Δx) - f(x) = f(1 + 3) - f(1) = 3√4 + 16 - 3
√1 - 4 = 6 + 16 - 3 -4 = 15.
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Masla
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Answers & Comments
x0=1
Δx=3
найти Δf(x)
Δf(x)=f(x0+Δx)-f(x0)=f(1+3)-f(1)=f(4)-f(1)=
=(3√4+4·4)-(3√1+4·1)=(6+16)-(3+4)=22-7=15
Verified answer
Простейшее задание на производные функции.Δf(x) = f(x+Δx) - f(x) = f(1 + 3) - f(1) = 3√4 + 16 - 3√1 - 4 = 6 + 16 - 3 -4 = 15.