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49617 $(2x+9)^2=(x-12)^2 \\ \\ (2x+9)^2-(x-12)^2=0 \\ \\ (2x+9+x-12)(2x+9-x+12)=0 \\ \\ (3x-3)(x+21)=0 \\ \\ 3(x-1)(x+21)=0 \\ \\ x-1=0;x=1 \\ \\ x+21=0;x=-21 \\ \\ otvet:1 \\ \\$

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maksimcat

Verified answer

(2x+9)²=(x-12)²
4x²+36x+81=x²-24x+144
4x²+36x+81-x²+24x-144=0
3x²+60x-63=0 (:3)
x²+20x-21=0
D=20²-4*1*(-21)=400+84=484=22²
x₁=(-20-22)/2=-42/2=-21
x₂=(-20+22)/2=2/2=1
Ответ: х=1

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