Ответ:

1. 3π - 4 - (√2/2)

2.

1) f'(x) = cosx - (1/sin²x)

2)  (2/cos²x) - (3/sin²x) - (3/x²)

Пошаговое объяснение:

1.

f'(x) = 4x - (2/cos²x) + cosx

f'(3π/4) = 4 * (3π/4) - (2/cos²(3π/4)) + cos(3π/4) =

= 3π - (2/(-√2/2)²) - (√2/2) = 3π - 4 - (√2/2)

2.

1) f'(x) = cosx - (1/sin²x)

2) 1/x³ = x⁻³

f'(x) = (2/cos²x) - (3/sin²x) - 3x⁻² =

= (2/cos²x) - (3/sin²x) - (3/x²)