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sese2
@sese2
August 2021
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A1.4) A2.1) A3.1) A4.3)
B1. А3 Б4 В5 Г1
В2. М (H3PO4)= 98 г/моль
98 г - 1 моль
19,6 г -х
х = 0, 2 моль
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Answers & Comments
B1. А3 Б4 В5 Г1
В2. М (H3PO4)= 98 г/моль
98 г - 1 моль
19,6 г -х
х = 0, 2 моль