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dentist344
@dentist344
August 2021
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ПОМОГИТЕ ПОЖАЛУЙСТА!!!!!!!!
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m11m
210.
1) √(√7 -2)² + √(√7 -5)² =√7 -2 +|√7 -5| =√7 -2 +5 -√7 = 3
2) √(√15 -2)² - √(√15 -3)² = √15 -2 - (√15 -3) = √15 -2 -√15 +3 =1
3) √√(28-16√3) = √√(4*(7-4√3)) =√2√(7-4√3)= √2√(2-√3)² =
=√(2*(2-√3) = √(4-2√3) = √(1-√3)² = |1-√3| = √3 -1
4) √√(68-√4608) =2 -√2
1) √(68-√4608) = √[
68+√(68²-4608)
] - √[
68 - √(68²-4608)]
=
[ 2 ] [ 2 ]
= √[(68+4)/2] - √[(68-4)/2] =√36 - √32 = 6 -√32
2) √(6-√32) = √
[6+√(6²-32)]
- √
[6-√(6²-32)]
= √[(6+2)/2] - √[(6-2)/2] =
[ 2 ] [ 2 ]
=√4 - √2 = 2 -√2
2 votes
Thanks 3
dentist344
СПАСИБО ТЕБЕ А КАК ТЕБЯ ЗОВУТ
dentist344
А ЧЕТВЁРТЫЙ
dentist344
НЕ УХОДИ
dentist344
КАК СДЕЛАТЬ ЧЕТВЁРТЫЙ ПОМОГИ ПОЖАЛУЙСТА
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Answers & Comments
1) √(√7 -2)² + √(√7 -5)² =√7 -2 +|√7 -5| =√7 -2 +5 -√7 = 3
2) √(√15 -2)² - √(√15 -3)² = √15 -2 - (√15 -3) = √15 -2 -√15 +3 =1
3) √√(28-16√3) = √√(4*(7-4√3)) =√2√(7-4√3)= √2√(2-√3)² =
=√(2*(2-√3) = √(4-2√3) = √(1-√3)² = |1-√3| = √3 -1
4) √√(68-√4608) =2 -√2
1) √(68-√4608) = √[68+√(68²-4608)] - √[68 - √(68²-4608)] =
[ 2 ] [ 2 ]
= √[(68+4)/2] - √[(68-4)/2] =√36 - √32 = 6 -√32
2) √(6-√32) = √[6+√(6²-32)] - √[6-√(6²-32)] = √[(6+2)/2] - √[(6-2)/2] =
[ 2 ] [ 2 ]
=√4 - √2 = 2 -√2