помогите пожалуйста. Created by Inetren. algebra-ru

Ответ: Д) .Ответ: В) .Ответ: А) .Ответ: Б) .

помогите пожалуйста...

$1)\; \; sin^2x-4sinx+3=0\\\\t=sinx\; ,\; \; |t|\leq 1\; ,\; \; t^2-4t+3=0\; \; \to \; \; t_1=1\; ,\; t_2=3\; (teorema\; Vieta)\\\\sinx=1\; ,\; \; x=\frac{\pi}{2}+2\pi n\; ,\; n\in Z$

Ответ: Д) .

$2)\; \; sin^2x-3sinx-4=0\\\\t=sinx\; ,\; |t|\leq 1\; \; ,\; \; t^2-3t-4=0\; ,\; \; t_1=-1\; ,\; t_2=4\; (teorema\; Vieta)\\\\sinx=-1\; ,\; \; x=-\frac{\pi}{2}+2\pi n\; ,\; n\in Z$

Ответ: В) .

$3)\; \; cos^2x-5cosx+4=0\\\\t=cosx\; ,\; \; |t|\leq 1\; \; ,\; \; t^2-5t+4=0\; ,\; \; t_1=1\; ,\; t_2=4\; (teotema\; Vieta)\\\\cosx=1\; ,\; \; x=2\pi n\; ,\; n\in Z$

Ответ: А) .

$4)\; \; cos^2x-4cosx-5=0\\\\t=cosx\; ,\; \; |t|\leq 1\; \; ,\; \; t^2-4t-5=0\; ,\; \; t_1=-1\; ,\; t_2=5\; (teotema\; Vieta)\\\\cosx=-1\; ,\; \; x=\pi +2\pi n\; \; ,\; \; x=\pi \, (2n+1)\; ,\; n\in Z$

Ответ: Б) .

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