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diar5
@diar5
September 2021
1
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помогите пожалуйста!
(х+ 3)^2×(х-2)×(х+5)^3 <0
(8-х)×(1+х)^2×(10-х)^3》0
(4х^2-4х+1)×(х^2+6х+5)《0
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Ambasada
1) (x+3)^2<0 (x-2)<0 (x+5)<0
x<-3 x<2 x<-5
x(-5;-3)∪(-3;2)
2) 8-x≥0 (1+x)^2≥0 (10-x)^3≥0
x≤0 x≥-1 x≤10
x(-∞;-1)∪(-1;8)∪(10;+∞)
3) 4x^2-4x+1≤0 x^2+6x+5≤0
x= 1\2 x=1; x=-5
x(-∞;1\2)∪(1\2;+∞) x(-5;1)
x[-5;1]
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Answers & Comments
x<-3 x<2 x<-5
x(-5;-3)∪(-3;2)
2) 8-x≥0 (1+x)^2≥0 (10-x)^3≥0
x≤0 x≥-1 x≤10
x(-∞;-1)∪(-1;8)∪(10;+∞)
3) 4x^2-4x+1≤0 x^2+6x+5≤0
x= 1\2 x=1; x=-5
x(-∞;1\2)∪(1\2;+∞) x(-5;1)
x[-5;1]