GoldmanYT Ответ:а) [tex] x \in \varnothing [/tex]б) [tex] x _ 1 = 0 \\ x _ 2 = 2 [/tex]Объяснение:а) [tex] 4 x ^ 2 + 1 = 0 \\ 4x ^ 2 = - 1 \\ x \in \varnothing [/tex]б) [tex] 3 x - x = x ^ 2 \\ 2 x = x ^ 2 \\ x ^ 2 - 2 x = 0 \\ x (x - 2) = 0 \\ x _ 1 = 0 \\ x _ 2 = 2 [/tex]