математик2011 1.
(3-х)²-(х-3)(х+3)+5х+22 = 9-6х-х²-х²+9+5х+22 = -х+40
2.
1) = 3m(1 - n)
2) = 4x³(2 - 3x³)
3) = (7 - c/3)(7+c/3)
4) = (8+y)(8+y) = (8+y)²
3.
= (1,7-x)(y-4,3)
Подставим значения 
= (1,7 - 0,2)(12,3 - 4,3) = 1,5*8 = 12
4.
1) = 2(9a²-6ab+b²) = 2(3a-b)²
2) = 3a(b+4) - 2c(b+4) = (b+4)(3a - 2c)
3) = x(x+2y) - 4(x+2y) = (x+2y)(x - 4)
5.
x²(x+2) - (x+2)(x² - x+3) = 0
(x+2)(x² - x²+x - 3) = 0
(x+2)(x - 3) = 0
x+2 = 0      x - 3 = 0
x = -2         x = 3

ЖИВИ!!!! И учи математику!:))