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микк3
@микк3
April 2021
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помогите пожалуста !!!!!!!
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DedushkaBake
(ky)'=ky', (UV)'=U'V+V'U
(ln2 *lnx sin2x)=ln2(lnx sin2x)=ln2[(lnx)'sin2x+(sin2x)'lnx]=
=ln2[(1/x)sin2x + 2cos2x lnx ]= ln2[(sin2x)/x+2(lnx)cos2x]
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(ln2 *lnx sin2x)=ln2(lnx sin2x)=ln2[(lnx)'sin2x+(sin2x)'lnx]=
=ln2[(1/x)sin2x + 2cos2x lnx ]= ln2[(sin2x)/x+2(lnx)cos2x]