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TiniLove
@TiniLove
June 2022
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Помогите пожаоуйста!!!!!!! Очень надо!!!!!!!
Докажите тождество:
а) (c-8)(c+3)= c в квадрате-5c-24
б) m в квадрате +3m-28=(m-4)(m+7)
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2407Alexa
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А)(с-8)(с+3)=с²-5с-24с²+3с-8с-24=с²-5с-24с²-5с-24=с²-5с-24-истино.c²-5c-24=0D=(-5)²-4*1*(-24)=25+96=121=√121=11c1=(-(-5)+11)/2*1=16/2c1=8c2=(-(-5)-11)/2=-6/2c2=-3(c-8)(c-(-3))=(c-8)(c+3)б) m²+3m-28=(m-4)(m+7)m²+3m-28=0По теореме Виетоm1+m2=-p=-3m1*m2=q=-28m1=4m2=-7(m-m1)(m-m2)=(m-4)(m-(-7))==(m-4)(m+7)истино
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Verified answer
А)(с-8)(с+3)=с²-5с-24с²+3с-8с-24=с²-5с-24с²-5с-24=с²-5с-24-истино.c²-5c-24=0D=(-5)²-4*1*(-24)=25+96=121=√121=11c1=(-(-5)+11)/2*1=16/2c1=8c2=(-(-5)-11)/2=-6/2c2=-3(c-8)(c-(-3))=(c-8)(c+3)б) m²+3m-28=(m-4)(m+7)m²+3m-28=0По теореме Виетоm1+m2=-p=-3m1*m2=q=-28m1=4m2=-7(m-m1)(m-m2)=(m-4)(m-(-7))==(m-4)(m+7)истино