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anandi98
@anandi98
July 2022
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Помогите прошу по алгебру
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Answers & Comments
PhiNicK
1) (8^(1/6)*9^(3/2)) / 8^(1/2) = (2^(1/2)*3^3) / 2^(3/2) = (√2*27)/(√2^3) = 27/2
2) ∛100*√2^(8/3)*(1/5)^(1/3) = 10^(1/3)*((√2)^8)^(1/3)*(1/5)^(1/3) = (2*(√2)^8)^(1/3) = 32^(1/3) = 2*∛4
3) (81^(3/4)) / 8^(7/3)= 3^3/2^7=27/128
4) (36/25)^(1/2)*(125/27)^(-1/3)= 6/5*(5/3)^(-1)=18/25
2 votes
Thanks 1
anandi98
Большое спасибо
PhiNicK
Во втором примере другое решение (10^2)^(1/3)*((√2)^8)^(1/3)*(1/5)^(1/3) = 320^(1/3)
anandi98
Большое спасибо
zarembo73
Решение задания на фото
1 votes
Thanks 1
anandi98
Большое спасибо
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Answers & Comments
2) ∛100*√2^(8/3)*(1/5)^(1/3) = 10^(1/3)*((√2)^8)^(1/3)*(1/5)^(1/3) = (2*(√2)^8)^(1/3) = 32^(1/3) = 2*∛4
3) (81^(3/4)) / 8^(7/3)= 3^3/2^7=27/128
4) (36/25)^(1/2)*(125/27)^(-1/3)= 6/5*(5/3)^(-1)=18/25