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cmokpubgmobile
@cmokpubgmobile
April 2022
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помогите прошу вас. Это срочно нужно дам 20 балов
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ksyuwi
Ответ:1)[tex]\frac{2}{3}*(27a-9b)-6*(4a-5b) =\frac{2}{3}*27a+\frac{2}{3}*(-9b)-6*4a-6*(-5b)=\\\\= \frac{2*27a}{3}+\frac{2*(-9b)}{3}-24a+30b=\frac{54}{3}a-\frac{18}{3}b-24a+30b= 18a-6b-24a+30b=\\\\=24b-6a[/tex]2)[tex]-(25x-3y)+\frac{1}{6}*(12x-12y)= -25x+3y+\frac{1}{6}*12x+\frac{1}{6}*(-12y)=\\\\=-25x+3y+\frac{12}{6}x-\frac{12}{6}y=-25x+3y+2x-2y=y-23x[/tex]3)[tex]1\frac{1}{3}* (27-3a)-(9-5a)=1\frac{1}{3}*27+1\frac{1}{3}*(-3a)-9+5a=\\\\=\frac{4}{3}*27+\frac{4}{3}*(-3)-9+5a= \frac{108}{3}-\frac{12}{3}a-9+5a=\\\\= 36-4a-9+5a=27+a[/tex]4)[tex](4m-5n)*(-6)+1\frac{1}{4}*(12m +8n)=-6*4m-6*(-5n)+1\frac{1}{4}*12m+ 1\frac{1}{4}*8n=\\\\=-24m+30n+\frac{5}{4}*12m+\frac{5}{4}*8n=-24m+30n+\frac{60}{4}m+\frac{40}{4}n=\\\\=-24m+30n+ 15m+10n=40n-9m[/tex]
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