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orxan2101
@orxan2101
March 2022
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pryanich
5t^2+20t-(t+4)=0
5t^2+20t-t-4=0
5t^2+19t-4=0
D=19^2-4*5*(-4)=361+80=441
t1=(-19-21)/5*2 = -40/10 = -4
t2=(-19+21)/5*2= 2/10 = 1/5
2 votes
Thanks 1
nastenasakharo1
5t²+20t-(t+4)=0
5t²+20t-t-4=0
5t²+19t-4=0
D=19²-4×5×(-4)=361+80=441=21²
-19+21 2
t₁= ₋₋₋₋₋₋₋₋= - ₋₋--- = -.0,2
2*5 10
-19-21 40
t₂= ---------- = - ----- = -4
2*5 10
Ответ: -0,2; -4
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Answers & Comments
5t^2+20t-t-4=0
5t^2+19t-4=0
D=19^2-4*5*(-4)=361+80=441
t1=(-19-21)/5*2 = -40/10 = -4
t2=(-19+21)/5*2= 2/10 = 1/5
5t²+20t-t-4=0
5t²+19t-4=0
D=19²-4×5×(-4)=361+80=441=21²
-19+21 2
t₁= ₋₋₋₋₋₋₋₋= - ₋₋--- = -.0,2
2*5 10
-19-21 40
t₂= ---------- = - ----- = -4
2*5 10
Ответ: -0,2; -4